One reservoir has four taps. Using the first takes two days to saturate the reservoir, the second tap three days, the third four days and the last one 6 hours.
What time will it last to fill the reservoir using all 4 taps at once?

Because there are 24 hours in one day, in one hour fills the first tap 1/48, the second tap
1/72, the third tap 1/96 and the fourth tap fills 1/6 of the reservoir. That is all together
(6+4+3+48) / 288 = 61/288. The reservoir will be full in 288/61 hours, which is 4 hours
43 minutes and about 17 seconds.

One reservoir has four taps. Using the first takes two days to saturate the reservoir, the second tap three days, the third four days and the last one 6 hours. 
What time will it last to fill the reservoir using all 4 taps at once?

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